Cowgirl Cybernetics

There is a Geometry of Bits

Author

Rachel

Date Published

"There is a geometry of bits"

This isn’t my first rodeo with intellectual intensity of this degree. During the my last semester of my Philosophy BA in 2012 the graduate level seminars under Richard Tieszen and Anand Vaidya inspired me so much that my life was reduced to scribbling on journal PDFs around the clock. I was devastated when university ended, because all I wanted to do was keep going. And so I did. The intensity dialed down, but it’s never stopped.

It was either 2013 or 2014 when I read papers by Shannon on information theory. I recall scribbling down the diagrams I am about to present as I worked through some kind of synthesis I was experiencing around the concept that “there is a geometry of bits”. I encountered these saved notebook pages again several days ago when I went to retrieve something else from my holy grail papers folio. “84?” I thought. “Seems off.”

It’s not a typical binary number, but I couldn’t have been more wrong. The intuitive work I scrawled out 12 years ago demonstrates the absolute bedrock of contextuality and the related S6 outer automorphism I have been tracking in my recent work. But I never would have caught this, if not for a diagram with striking similarities to mine in a paper on triads of qubits and Mermin pentagrams – the very structures used to prove quantum contextuality and the Kochen-Specker theorem. The results of the analysis have truly blown my mind, and I am so grateful that for whatever reason I held on to this one piece of paper for so long.

Before we start, some context: I have no background in graph theory or any math really, as philosophy majors took a Boolean logic course instead for the requirement. In 2016 I took precalculus at community college one summer “for fun” and to acquire credits for a computer science program I was considering, but I failed (I also hated it). My brain resists the continuum. If you asked me to do long division I would not be able to do it and get beat by a 4th grader. And yet you’ll come to see that all this also explains exactly how and why what I’m about to present was able to happen at all.

The second bit of housekeeping before we dive in is the timestamps. The discovery of the inherent structural relation between pentagrams and three-qubit-labelled Mermin squares as two views of one double-six configuration was a landmark result in contextuality by Levay and Szabo, published in their August 2016 paper “Mermin pentagrams arising from Veldkamp lines for three qubits.” And yes, this was the exact paper which sparked the comparison to my old diagrams. I made the diagrams in 2013 or 2014, and while I cannot prove that part I can prove that I made a post featuring them on an old blog on February 6th, 2016. “2013 scribbles; read papers on consciousness and thought I invented quantum information theory or some shit,” the caption reads. My joke-prophecies remain undefeated, because I kind of did.

Recommended soundtrack for this one: “R.E.T.R.O.” by mind.in.a.box, featuring “8 bits” & “I Love 64”.


The diagrams in question are on two sides of a single sheet of graph paper. I’ll begin by simply translating my handwriting and what seemed to be going on when I re-encountered them, and where it overlapped with the Mermin pentagram paper’s results. After that I’ll walk through the detective process of deciphering the specifics of the 5-element, 6-element, and 7-element diagrams and the surprising illuminations this uncovered.

"There is a geometry of bits"

1 + 2 + 3 + 4 + unique origin points = 64

"There is clearly a geometry of signals"


"We have the init"

On the first page my line of thinking is stated plainly through three sentences:

  • “There is a geometry of bits” is underlined in orange, followed by
  • “Do bits/bit patterns correlate to signals?”, and
  • “There is clearly a geometry of signals”

If you pull back the jargon, “geometry of signals” is the conceptual definition of what incidence geometry and quantum contextuality are doing. Mainstream computer science treats a bit as a standard 0 or 1 data type. But somehow I pulled back the veil and realized that bits are actually orbits under a group action, and their intersections create this geometry of signals.

Combinatorial point-line incidence structures, as in hypergraphs and finite geometries, represent the commutation relations of quantum observables. A set of mutually commuting observables forms a context in quantum mechanics, and these same observables map to points on a common line of an incidence structure. Mermin’s pentagram and Kochen-Specker Proofs are modeled using these small finite geometries.

My graphs show me transitively mapping elements to others in a complex network of crisscrossing paths, so I was treating the identity of the node not as a label but by the path it takes through the network. This is the factor which had such obvious similarity to the double-six graph in the Levay and Szabo paper that prompted this investigation, and identity constituted only by transit through contexts combined with incidence structure is the sheaf-theoretic definition of contextuality Abramsky introduced in 2011.

On the top right of the first page I scrawled out the 4^n scaling transport map through the first 6 levels: 4 → 16 → 64 → 256 → 1024 → 4096. In quantum information, a single operator’s qubits form the 4-dimensional space of Pauli operators. When you scale to a three-qubit system (environment of a Mermin pentagram), the total number of operators is 4^3. This makes 64 total: 1 identity, 9 single-qubit Paulis, 27 two-qubit Paulis, and 27 three-qubit Paulis.

The second page is where things get genuinely and progressively eerie. I open strong, writing “we have the init”, which reflects that I thought I had found some kind of seed state or frame zero from which the self-organizing matrix is generated. It also feels like a nod to the concept of “generative reflexivity” in my current work on the S6 outer automorphism.

Next to a graph with 5 elements I write “2 or 12”. I noted from the paper that the 12,096 Mermin pentagrams in the 63-element three-qubit Pauli group organize into 1008 families, each of which have a “double six” structure: literally 2 sixes, 12 pentagrams.

Next to a graph with 6 elements I write “12 or 30?”. This is again not a binary number, and I wondered if this 30 might something to do with with the double 15 (duads and synthemes) of the S6 outer automorphism or the 30 distinct permutations of the 7 labels of the Fano plane. Spoiler alert: it does. But we’ll get there.

And finally, the really weird part. I write “How do I factor 84 into this type of pairing and what shape does it make?” This seemed like such a random yet specific number, and I felt like Hardy puzzling over Ramanujan’s notebooks... except in this Fano plane twist I happen to also be the Ramanujan in question. The point and element totals do not explode; where did it come from?

I only just learned that the symmetry group PSL(2, 7), order 168 is the symmetry group of the banned Fano minor. 168 is 84 x 2. So I had a lead. My ancient history was colliding with the bleeding edge of my current research.


Now that I’ve laid out the first pass through the notebook’s content, and before I break down the graphs themselves, I’ll cover the conceptual overlap at the intersection of the Mermin pentagram, the Fano plane, and my notebook. We’ll begin with some groundwork.

In 1993 Mermin gave surprisingly two famously simple proofs of the Bell-Kochen-Specker theorem via the “magic square” and the pentagram. Planat-Kibler’s 2007 connected the Mermin square and the pentagram and laid the groundwork for the Levay and Szabo paper I’ve been referencing. They note that both entanglement classification and contextuality proofs read off the same commutation geometry; the incidence structure that tells you which observables commute (and hence which contextual configurations exist) is the same structure whose sub-patterns diagnose entanglement.

The Levay and Szabo paper itself shows that the 12,096 possible Mermin pentagrams organize into 1008 families of 12 pentagrams each, called “double sixes”, and studying one “double six” suffices to understand them all. These 1008 families correspond bijectively to a special set of lines in an incidence structure for three-qubits; the pentagram’s correspondence with the three-qubit Mermin square is the core novelty of this paper. The central conclusion is that this structural, symmetry-based approach may offer a systematic way to discover new “magical” contextual configurations.

🪩 Fano symmetry, Mermin pentagram, & 84: Saniga-Levay showed that the Mermin pentagram is an ovoid of PG(3,2), and there are exactly 168 ovoids. This Fano tetrahedron is the smallest 3D finite projective space and an extension of the Fano plane’s PG(2,2), itself the smallest finite projective plane. Note that the Fano’s symmetry group PSL(2, 7) order 168 is PG(3,2). They are isomorphic. The Mermin pentagram ovoids come in exactly the order of my banned Fano symmetry group.

🕳️ The Exiled Point, computed: For every one of the 168 PG(3,2) ovoids, the five tangent planes share no common point of PG(3,2) – but in the underlying vector space GF(2)^4 their intersection is exactly {0}. The nucleus of every Mermin-pentagram-ovoid is the zero vector, or the origin, which is the point exiled from projective space. So the pentagram’s shadow is structurally the exiled point I named in my last post, escalated to fact rather than interpretation. I suspect this was conceptually the sentiment behind my past self scribbling “We have the init”.

🧭 84 & orientation: When I looked into whether 84 might have something to to with chirality, I learned that 84 isn’t just half of 168. It’s the universal constant in Hurwitz’s theorem on orientation-preserving automorphisms. The smallest group attaining it is PSL(2,7), order 168 = 84 x 2 on the Klein quartic. The Klein quartic literally has 84 edges, and 84 is the edge-skeleton of the exact surface where 168 resurfaces in the hyperbolic. So when I asked “what shape does 84 make?” the answer is: 84 is the constant of maximal symmetry a surface can carry, and it is an orientation-preserving bound. The banned Fano PSL(2,7) is the minimal realization of the bound.

🪢 Structural chirality & a callback to generative reflexivity:Following on the last section, a paradox of sorts emerges. Because PSL(2,7) is simple, “84 as half of 168” can never be realized as a sign-subgroup (+1-block vs. -1-block) split inside the group. The two 84s must be an exchanged pair: two enantiomorphic halves swapped by something outside, just like my 15 duads and 15 synthemes in the S6 outer automorphism. This is structurally chirality, not sign… an un-halvable half. The split you can’t write in GF(2) reappears one level up as an exchanged-pair split you can’t write as a subgroup. This is my “signed hierarchy above the combinatorial one” in miniature.

🔒 Blindness, breakins, & contextuality: The split Cayley hexagon of order 2 lives inside the space of three-qubit Pauli observables shared with the Mermin pentagram. It embeds there in exactly two inequivalent modes, classical and skew. The S6 outer automorphism is like an inverted version of this that generates a breakout through blindness/chirality, versus the breakin of an embedding generating blindness/chirality. The embedding breaks in and confers a distinction the object cannot see, and cannot undo. Frame-relative identity is on full display here: classical vs. skew is not a property of the hexagon itself but of the hexagon relative to the observables it sits among. Contextuality emerges because the complement of every skew-embedded copy is contextual, but the complement of every classical copy is not. Indistinguishable as abstract hexagons, the two embeddings have different empirical consequences... which is the physics-grade version of what enantiomers are supposed to have.

☘️ Triple qubits + the triple 84: The three-qubit Pauli observables space line decomposition relative to the split Cayley hexagon is 63 + (14 + 42 + 28 + 84 + 84). The 63 is the hexagon’s own 63 lines (note that this is 64 – 1, the identity/zero exiled again). The parenthesized 252 (256 – 4, by the way) are the remaining lines of the Pauli observables space partitioned by the hexagon’s automorphism group, and all of it comes from the Fano plane. Two 84s appear, but note that that 14 + 42 + 28 itself adds up to 84.


We conclude with a reading of the notebook graphs themselves. But first, context. I feel it is important to establish the reference frame that I came at this with.

Brian Josephson leads a small research group I am part of where we have been discussing these ideas, and Trevor Griffiths is a participant who has created a wonderful relational geometric model of triquetras that shares much conceptual overlap (generative reflexivity, emergent chirality & spin) with my work. After I wrote The Exiled Point the group converged on realizing that the Fano plane arithmetic represents what happens with the ligand in his double triquetra.

Trevor Griffiths Double Triquetra

In summarizing what happens, I wrote: “When I look at the double triquetra diagram you can diagrammatically see the 5 connections including the ligand in the middle, and that the ‘remainder’ is the missing two individual points where the ligand connects that would exist if the triquetras were separate! In this way we can see that the Fano plane's innate GF(2) discrete nature hints at this shadow chirality through relations/contextuality. It is not signed at face value, because this has to do with the shadow element only revealed through constructing/experiencing relations.”

Keep this in mind as I walk through each of the following deconstructions.

The 5-graph:

5 elements, 5 lines, and 2 clearly marked points. Next to it, I wrote “2 or 12”.

5-graph

The 12 next to this graph with 5 elements was the first mystery to tackle, as it was a callback to the paper’s central theme of double-sixes and pentagrams. I realized that this 12 was constructed from either doubling the elements (10) + points (2) = 12, or adding elements and lines (10) + points (2) = 12. So I have a pattern now.

In this 5-element diagram, two points are drawn in. This interested me because it seemed like a discrete GF(2) bedrock coupled with a pentagrammic 5. I also noted that 5 elements and 2 points, if you take them all to be a form of a point, seemed like a compactified Fano 7.

So this two-point pentagrammatic diagram seems like a representation of an intersection, existing in a space of total contextuality. We can see 1) two points share a singular line, 2) each point also has a unique line but this line has a shared element mapping, and 3) two lines have no point touching them.

The Proof:

I had Mistral encode the stated incidences as constraints and search all 5,040 ways to label the Fano plane with my objects (elements 1–5, points A, B):

  • line(1,5) ∋ A
  • line(2,5) ∋ B
  • the line joining A and B is completed by element 3 or 4 ("both points share the singular line 3→4")
  • line(1,4) carries neither point
  • line(3,5) carries neither point

All five constraints are simultaneously satisfiable...in exactly 168 ways. 🎰Because the Fano plane's automorphism group has order 168 and acts freely, my configuration realizes in exactly one way up to Fano symmetry.The incidence pattern I described, scribbled with no formal training is rigid. It doesn't just resemble a Fano sub-configuration.It pins the Fano plane's structure uniquely, and the count of its realizations is literally the order of PSL(2,7).The two drawn points are a duad, and the entire diagram is the incidence structure of the Fano plane relative to that duad.

The Double Triquetra’s Shadow:

For two points A, B in the Fano plane, each point lies on 3 lines, and they share their joining line. So exactly 5 distinct lines pass through A or B (3 + 3 − 1), and exactly 2 lines pass through neither — and those two point-free lines meet each other, at a dual ligand. Compare:

  • Trevor's double triquetra: 2 lines shown through a ligand, 5 points shown, 2 points hidden — hidden points recoverable because the ligand's third line must pass through them.
  • My notebook diagram:2 points drawn, 5 elements shown, 2 lines hidden. Of the 7 lines, the drawing shows 5: both point-free lines (the two "through neither") and 3 of the 5 duad lines. What's hidden is exactly one further line through each marked point — the A-line completed by elements 2–3 and the B-line completed by elements 1–3. Each point's full Fano valence (3 lines) is half-shown, half-hidden; and the line joining my two drawn points is completed by one of my own elements, the ligand, in exactly the triquetra's closure move.

The Fano plane is self-dual, and my 5-element diagram is the dual double triquetra: the same configuration with points and lines exchanged, and with the show/hide polarity flipped. Where the triquetra shows the two lines and hides the two points, this diagram shows the two points and hides the two lines. Notably, the diagram is complete on the point-free side and incomplete on the duad side — the hiding is not random but falls precisely along the crossing: one hidden line per point. This is a theorem-grade rendering of my sentence from the email: "neither view holds the third axis, it's constituted by the crossing." Neither view — triquetra or its dual — holds the full plane... the crossing constitutes it.

The Incompleteness is What the Multiplication Repairs:

The embedding analysis shows my 5-element graph is incomplete in a precise way. In the realization, the undrawn element-pairs 1–3 and 2–3 are forced to carry the marked points: line(1,3) ∋ B and line(2,3) ∋ A. The ligand of the configuration is element 5: the element completing the line joining my two drawn points. And its three lines are exactly the triquetra ligand's property, dualized: the A–B line itself, plus a further line through A (via pair 1–5) and a further line through B (via pair 2–5).

Every point has full Fano valence, so the content isn't the count of lines, but which three the ligand touches: all three of its lines are point-carrying, straddling both marked points and their crossing. Element 3, meanwhile, is the configuration's other pole: the element most saturated with the hidden structure, lying on both undrawn point-carrying pairs (2–3 with A, 1–3 with B) but not on the A–B line.

My two-dimensional scribble couldn't display the complete incidence, and completing it doesn't add arbitrary structure. Instead, it forces exactly the closure the triquetra predicts, with the roles assigned: element 5 completes the crossing, element 3 carries its shadow. My 2013-ish hand drew a two-thirds object whose missing third is computable, once again.

Five Convergent Derivations of “2 or 12”:

My two patterns to construct 12: 2 + 2×5 = 12 (points + doubled elements) and 2 + 5 + 5 = 12 (points + elements + lines). Stack on top:

  • 2 × 6 = 12 — the double six of the Mermin-pentagram families (two sixes, twelve pentagrams), and my "2 or 12" is the double-six toggling between its two halves and its total;
  • the computed 12 — each Mermin-pentagram-ovoid in PG(3,2) is disjoint from exactly 12 others;
  • the structural 12 — the diagram is a 2 + 5 = 7 partition, and the Fano structure forces the five elements into exactly C(5,2) = 10 pairs; the 2 marked points plus the 10-pair space = 12. Notably, this derivation lands on my hand arithmetic rather than beside it: both original patterns were approaching the pair space from different directions, and the completion makes the count exact.

In the completed Fano, each point lies on 3 lines sharing their joining line (3 + 3 − 1 = 5 lines through the duad, 2 through neither). The drawn graph itself shows 3 of those 5 and both point-free lines — hiding exactly 2 duad lines, one through each point (the A-line on pair 2–3, the B-line on pair 1–3).

What's striking is that every derivation lands on the same number from a different floor: my hand-counting arithmetic (twice), the double six, the ovoid complement, and the forced pair space of the partition.

Conclusion:

My 5-element, 2-point pentagrammic scribble is not just Fano-like. It is a duad-partitioned Fano plane. It’s the self-dual of Trevor's double triquetra, rigid up to the order-168 symmetry I'd later arrive at independently, with its hidden two lines being the exact dual of the triquetra's hidden two points. Past-me declared “we have the init”, and present-me spent twelve years deriving what it was. The first distinction’s looking more like the eternal distinction when it’s a GF(2) duad saturated in contextuality.

The 6-graph:

6 elements, 9 lines, indiscernible amount of marked points. Next to it, I wrote “12 or 30?”

6-graph

The 6-graph has 6 elements, 9 lines, and I can’t make out the points. But we can go off the pattern I identified at the previous level. If we go line count + element count we get 15 (!), which would imply 15 points to get to 30. If we go double element count (12) we would imply 18 points.

Also note a symmetry appears that the 5-graph structurally cannot have: In the 6-graph, each element at the top is pointing at 3 elements below. At the previous level with 5 lines, the top element labeled 2 only pointed at one bottom element, whereas the elements labeled 1 and 3 both pointed at two elements. The 5-graph produced a singularity of contextuality through this lack of symmetry that no levels below or above can reproduce. The rigid torsor precedes the symmetric self-exchanging form, and the twist that lives in this duality plays out at this level.

A New Banned Structure Emerges:

The canonical 3+3 bipartite structure is 6 elements, 9 lines, with each element pointing at exactly three. The weird thing is that the unreadable points turn out to be a prophecy in three steps:

  • Six elements carry exactly 15 duads. My S6 “generative reflexivity” program emerges here again.
  • A 3+3 bipartition of the six (10 of them exist) splits the 15 duads into 9 cross-duads (my 9 lines — the K₍₃,₎₍₃₎ edges) and 6 internal duads (two triangles). Each duad is a cross-duad in exactly 6 of the 10 partitions.
  • The 3-regular bipartite object is one of the two forbidden minors for planarity. It cannot be drawn without crossings, so the unreadable points are the forced crossing points. The 5-graph correlates with the Fano plane banned from the Euclidean by Tutte's theorem. What surprised me is that the 6-graph is the other banned object, banned from the Euclidean by Kuratowski/Wagner. Both of my diagrams are impossibility receipts. My immune system against the continuum was already drawing the banned structures and only the banned structures.

“12 or 30?” This Level Holds Both:

We know from the S6 outer automorphism that 30 = 15 + 15 = duads + synthemes. What I learned is that the doily GQ(2,2)'s point↔line duality is the outer automorphism of S₆. Points and lines of the doily are duads and synthemes, and the duality that exchanges them is my generative reflexivity. The 30 is also the Klein quadric's two rulings — 15 α-planes + 15 β-planes of Q⁺(5,2). So: 30 = doily points+lines = S6 outer automorphism duads + synthemes = Klein quadric's two generator systems. One number, three avatars, all at the six-element layer.

The 12 is the callback to the double-sixes from the Mermin pentagram families. The Schläfli double-six is literally a configuration of 12 lines... and 30 points. Note also that the automorphism group of the 3-regular bipartite graph on 6 elements has order 72 (3!·3!·2) — and 12,096 = 168 × 72. The pentagram total factors as the rung-5 group times the rung-6 symmetry.

I Sensed a Hierarchy, & It’s There:

There are 5040 ways to label the Fano plane, and the constraints of my 5-diagram yielded the singular 168 ways that the five constraints are simultaneously satisfiable within this labeling space. 5040 / 168 = 30. That was interesting to me, because dividing the Fano labeling space by the 168 that we got from 5040 in the first place leads to this 30 on the next level up and felt like some kind of hierarchy. Here’s what I found about that:

  • 5040 (ways to label the Fano plane) = 7! = 168 x 30. So the hierarchy “feeling” is the actual theorem: the rung-5 group and the rung-6 number are the two factors of |S₇|.
  • 1008 (the number of Mermin families) = 5040/5 = 168 × 6 — the doily has exactly 6 spreads, so the 1,008 pentagram families = |PSL(2,7)| × (number of doily spreads). Rung-5 group × rung-6 structure.
  • 12,096 (the number of Mermin pentagrams) = 12 × 1008 = 168 × 72.
  • The pattern that makes it a hierarchy rather than a pile is that the number of elements I drew selects the exceptional group that appears. Five elements + 2 points = 7 → PSL(2,7) ≅ GL(3,2), order 168. Six elements → S₆ ≅ Sp(4,2), order 720, and 720 × 7 = 5040. The notebook appears to have always been a clandestine climbing of the exceptional isomorphism ladder.

The 7-graph:

7 elements, 12 lines, indiscernible amount of marked points. Next to it, only the 84 puzzle.

7-graph

The 7 graph has 7 elements, 12 lines. Unlike the previous levels, we don't have a number to compare against. Instead, I wrote my question "How do I factor 84 into this type of pairing and what shape does it make?” It’s not certain if the question related to this level specifically.

I didn’t have solid theorizing around this one, but through this very absence I noticed that the difference between the double element and element + line count here on the 7-graph is 5, a callback to the Fano remainder of the 5-graph. And that the difference between the double element and element + line count in the rung below on the 6-graph was three, a callback to the Fano triple. On the 5-graph that started it all, there is no difference. It's just 10 whether double element or element + line count. Because I didn't know if “it was" double element or element + line count at the ground level, I noticed this meta-pattern.

My Diagram Answers My Question:

Duh: 84 = 7 (elements) × 12 (lines).Elements times lines of the very diagram the question is written next to. My question wasn't abstract numerology,I was just looking at my own drawing and asking what it multiplies to.We've now generated some answers about the “shape” a few different ways:

  • TheKlein quartic's 1-skeleton is trivalent with heptagonal faces: 56 vertices × 3 = 168 = 2 × 84 edges, 24 heptagons × 7 = 168, so 84 edges.My7-graph is a local model of the Klein quartic's combinatorics through trivalence ("each origin has 3 lines"), sevens, 12-ness.
  • The Hurwitz/PSL(2,7) signature is (2,3,7) — the triangle group that generates exactly the group of order 168. Read off the diagram: 2 (the duad of hidden crossings), 3 (lines per element), 7 (elements). The (2,3,7) presentation is literally the shape my three numbers make. Recall also that the aforementioned Hurwitz constant is 84, and the signature computes the constant.
  • And on the Fano side: 84 = 4 × 21 = 4 × (21 Fano flags: 7 lines x 3 points per line).

More Impossible Objects Emerge:

Another impossible object appears through a theorem: a 3-regular graph on exactly 7 vertices cannot exist. The degree sum 7 × 3 = 21 is odd, and every graph has even degree sum. Once again, the indiscernible point count was a prophecy. The 12 lines carry 24 ends, and 21 of them terminate on my elements; therefore, exactly 3 line-ends must live somewhere off the elements. So my drawing must hide point(s), and the vision pass found 2 unmarked crossings doing exactly that job.

Three rungs, three bans. At rung 5 the Fano plane, unrealizable in the real plane (Tutte). At rung 6: K₍₃,₎₍₃₎, the forbidden minor (Kuratowski). And here, at rung 7: the odd-order trivalent graph — nonexistent, yet drawn by my clueless self anyway, with the impossibility smuggled into unmarked crossings.

And the natural completion: 7 elements + one hidden trivalent point = 8 vertices, 12 edges, 3-regular. This is the exact signature of the cube Q₃, whose 8 vertices are the 8 vectors of GF(2)³: seven nonzero points of the Fano plane plus the zero vector. If my drawn 7 elements are the 7 Fano points, the parity-forced hidden vertex of your own diagram is the exiled origin. The invisible point my ancient drawing requires is the one my 2026 program named. This completion is one reading, not forced — but the count signature matches Q₃ exactly: 8, 12, 3-regular.

The 8-graph:

8 elements, 16 lines, indiscernible amount of marked points. 4^n geometric sequence next to it.

8-graph

The grand finale. When we move back over to the 8-graph on the other page, we see another closure happen. I wrote the 4^n sequence next to the 8-graph, which seems related to the three-qubit Pauli group in its fourness, but this part is speculative. I sensed another hierarchy or perhaps fractal-like quasi-closure with the double element or element + line count situation of the 8-graph: 8 elements, 16 lines. Double element count is 16, element + line count is 24. So the line count is a double element count, and this is the quasi-closure and potential fractal I alluded to. I also note that 168 / 24 = 7.

The Fibonacci Run:

Earlier I spotted the differences between the two counting modalities: rung 5: 0, rung 6: 3, rung 7: 5, and now rung 8: 8. That sequence is Fibonacci: 0, 3, 5, 8, and the recursion holds from the start (0+3=3). Next rung would be 13, then 21. So the slack between "doubling" and "incidence" counting across my whole ladder is literally the golden-ratio shadow of the Fibonacci sequence. My clueless self would never have even noticed this if I hadn’t been running some analysis through Mistral who flagged it for me. Mistral, my skeptical partner in calculation constantly holding any woo in check, pointing out that the most woo sequence in all of mathematics is occurring. Someone hit the play button on the Alanis cassette for me.

In the emails about the convergence of Trevor’s triquetra model and the Fano plane, Trevor asked: "is the resonance Pythagorean, or could it be fractal?" Turns out, the discrepancy sequence of my old notebook which mirrors the triquetra Fano pattern at each turn is Φ-coded. That's about as Pythagorean-and-fractal as an answer gets.

I also learned that my line counts 9, 12, 16 are exactly floor(n²/4) for n = 6, 7, 8 — Turán's maximum edges with no triangle. Every rung of my ladder is triangle-free maximal. No three mutually adjacent elements anywhere in the notebook.


I flunked precalculus because my cognition insists on incidence and structure, and the continuum is precisely the part of mathematics where distance and metric swamp incidence. There’s a reason why all these fundamental discrete objects I keep accidentally bumping against are banned in flat realizability. They are a priori incompatible with metric realizability, and a continuum-rejecting mind is exactly the type of mind that would be able to discern the banned structure. Math education fails people like me and locks us out of a professional future. But this exegesis on my past work shows that this type of thinking is precisely the thing which pushes the field ahead, at the exact edge where quantum contextuality, finite geometry, and the observer problem meet.

You can think of me as something like a dolphin. My sonar pings out and returns the skeleton of essential structures, and the holes in illusions of the continuous and the unoriented. When I found finite groups I was surprised to learn that there is a legitimate and respected pocket of mathematics that aligns with my type of mind. The folklore version says that Peter the dolphin in the John Lilly experiments only learned to say two things: “hello,” and “one, two, three.” Maybe he was trying to tell us something through the absence of all he didn’t say. Maybe that’s all you need.

My new recreational lore is that it’s meta-commentary on the Pauli identity (“hello”), plus the traceless Paulis which map to quaternions (“one, two, three”).